When Neil Robertson faces John Higgins in the Wuxi Classic, it will be the second time they've met in a final already this season - and it promises to be a blinder.
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| Picture by Monique Limbos |
These two great champions have been the best players in the tournament by quite a distance.
Higgins has got here losing just six frames all week while Robertson has gathered momentum and now looks back to a level somewhere his very best.
They both ran out comfortable 6-2 winners in the semi-final matches, but now the biggest test is to come.
People were writing Higgins off at the back end of last season, consigning his best performances to history. But the Scot has looked solid all week, comfortably picking off his opponents while they searched for their rhythm. He's proved the theory correct that form is temporary and class is permanent.
He is a snooker legend. It was 15 years ago when he picked up the first of his four world title wins and he's still competing at the very top of the game today. This is a sign of his greatness.
Robertson has everything he needs to become a great. He was absolutely awesome against Robert Milkins and looks like he's improving with every match. This is exactly how you win big titles, by saving your best for last.
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| Picture by Monique Limbos |
He has every attribute required to gone on and win lots of trophies. Victory here would be a statement of intent for the rest of the campaign.
The final is a race to ten frames and should be a fantastic match. It is difficult to pick a winner, but the form guide favours Higgins. He beat Robertson 4-1 in the final of the Bulgarian Open just two weeks ago and has also won all of their past four head-to-head meetings.
It's tough to pick an area where this match may be won or lost, but players are so good at front running matches that I believe the first session of this final could be more pivotal than in most.
Let's get ready for what could be a classic.
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